Let's dig a little more into it using following example: Employer (1-*) Employee (1-*) Benefit (See below for DB tables and their content). Entity model for this situation will look like this:
@Entity
@Table(name = "EMPLOYERS")
public class Employer implements Serializable {
private String businessName;
private List<Employee> employees;
private Long id;
@Column(name = "BUSINESS_NAME")
public String getBusinessName() {
return businessName;
}
@OneToMany(mappedBy = "employer")
public List<Employee> getEmployees() {
return employees;
}
@Id
public Long getId() {
return id;
}
...
}
@Entity
@Table(name = "EMPLOYEES")
public class Employee implements Serializable {
private List<Benefit> benefits;
private Employer employer;
private String firstName;
private Long id;
@OneToMany(mappedBy = "employee")
public List<Benefit> getBenefits() {
return benefits;
}
@ManyToOne
@JoinColumn(name = "EMPLOYER_ID")
public Employer getEmployer() {
return employer;
}
@Column(name = "FIRST_NAME")
public String getFirstName() {
return firstName;
}
@Id
public Long getId() {
return id;
}
...
}
@Entity
@Table(name = "BENEFITS")
public class Benefit implements Serializable {
private Employee employee;
private Date endDate;
private Long id;
private String name;
private Date startDate;
private BenefitType type;
@ManyToOne
@JoinColumn(name = "EMPLOYEE_ID")
public Employee getEmployee() {
return employee;
}
@Column(name = "END_DATE")
@Temporal(TemporalType.DATE)
public Date getEndDate() {
return endDate;
}
@Id
public Long getId() {
return id;
}
@Basic
public String getName() {
return name;
}
@Column(name = "START_DATE")
@Temporal(TemporalType.DATE)
public Date getStartDate() {
return startDate;
}
@Column(name = "BENEFIT_TYPE")
@Enumerated(EnumType.STRING)
public BenefitType getType() {
return type;
}
...
}
Time for real fun :) - let's query the DB using following DAO:public class DefaultEmployeeDAO implements EmployeeDAO {
@PersistenceContext
private EntityManager entityManager;
public Employee get(Long id) {
return entityManager.find(Employee.class, id);
}
...
}
Executed SQL queries depend on used JPA provider:-- Hibernate 3.4.0.GA
select employee0_.id as id1_1_, employee0_.EMPLOYER_ID as EMPLOYER3_1_1_, employee0_.FIRST_NAME as FIRST2_1_1_, employer1_.id as id2_0_, employer1_.BUSINESS_NAME as BUSINESS2_2_0_
from EMPLOYEES employee0_ left outer join EMPLOYERS employer1_ on employee0_.EMPLOYER_ID=employer1_.id
where employee0_.id = 1
-- EclipseLink 2.1.1
SELECT ID, FIRST_NAME, EMPLOYER_ID FROM EMPLOYEES WHERE (ID = 1)
SELECT ID, BUSINESS_NAME FROM EMPLOYERS WHERE (ID = 1)
-- OpenJPA 2.0.1
SELECT t1.id, t1.BUSINESS_NAME, t0.FIRST_NAME
FROM EMPLOYEES t0 LEFT OUTER JOIN EMPLOYERS t1 ON t0.EMPLOYER_ID = t1.id
WHERE t0.id = 1
As you see @ManyToOne mapping causes fetching the referenced entity along with the referencing one (fetch type EAGER), while fetching entity mapped with @OneToMany is deferred until it will be accessed for the first time (fetch type LAZY).
Take a deeper look at the queries generated by EclipseLink. What the heck!? Why they don't use joins?! And what we can do about it?
This is the situation where @JoinFetch comes to the rescue - but be aware - this annotation is EclipseLink addition to JPA and hence makes your mappings not portable across the different providers! How can it be used? see example below:
@ManyToOne
@JoinColumn(name = "EMPLOYER_ID")
@JoinFetch(JoinFetchType.OUTER)
public Employer getEmployer() {
return employer;
}
After adding the @JoinFetch your EclipseLink SQL queries will turn into:SELECT t1.ID, t1.FIRST_NAME, t1.EMPLOYER_ID, t0.ID, t0.BUSINESS_NAME FROM EMPLOYEES t1 LEFT OUTER JOIN EMPLOYERS t0 ON (t0.ID = t1.EMPLOYER_ID) WHERE (t1.ID = 1)
Let's back to the @OneToMany annotation for a while, and check how the providers will behave when we change the default fetch type to EAGER, in following way:
@OneToMany(mappedBy = "employee", fetch = FetchType.EAGER)
public List getBenefits() {
return benefits;
}
This time the SQL queries are:-- Hibernate 3.4.0.GA
select employee0_.id as id1_2_, employee0_.EMPLOYER_ID as EMPLOYER3_1_2_, employee0_.FIRST_NAME as FIRST2_1_2_, benefits1_.EMPLOYEE_ID as EMPLOYEE6_4_, benefits1_.id as id4_, benefits1_.id as id0_0_, benefits1_.EMPLOYEE_ID as EMPLOYEE6_0_0_, benefits1_.END_DATE as END2_0_0_, benefits1_.name as name0_0_, benefits1_.START_DATE as START4_0_0_, benefits1_.BENEFIT_TYPE as BENEFIT5_0_0_, employer2_.id as id2_1_, employer2_.BUSINESS_NAME as BUSINESS2_2_1_
from EMPLOYEES employee0_ left outer join BENEFITS benefits1_ on employee0_.id=benefits1_.EMPLOYEE_ID left outer join EMPLOYERS employer2_ on employee0_.EMPLOYER_ID=employer2_.id
where employee0_.id=1
-- EclipseLink 2.1.1 (without @JoinFetch)
SELECT ID, FIRST_NAME, EMPLOYER_ID FROM EMPLOYEES WHERE (ID = 1)
SELECT ID, BUSINESS_NAME FROM EMPLOYERS WHERE (ID = 1)
SELECT ID, START_DATE, NAME, END_DATE, BENEFIT_TYPE, EMPLOYEE_ID FROM BENEFITS WHERE (EMPLOYEE_ID = 1)
-- OpenJPA 2.0.1
SELECT t1.id, t1.BUSINESS_NAME, t0.FIRST_NAME, t2.EMPLOYEE_ID, t2.id, t2.END_DATE, t2.name, t2.START_DATE, t2.BENEFIT_TYPE
FROM EMPLOYEES t0 LEFT OUTER JOIN EMPLOYERS t1 ON t0.EMPLOYER_ID = t1.id LEFT OUTER JOIN BENEFITS t2 ON t0.id = t2.EMPLOYEE_ID
WHERE t0.id = 1 ORDER BY t2.EMPLOYEE_ID ASC
Both Hibernate and OpenJPA generate impressive queries :) - but in fact they are using the most efficient way to fetch all correlated entities.Quick note for OpenJPA users - the above example leads to an exception while processing the results:
<openjpa-2.0.1-r422266:989424 nonfatal general error> org.apache.openjpa.persistence.PersistenceException: null
FailedObject: ... .entities.domain.Employee-1 [org.apache.openjpa.util.LongId] [java.lang.String]
at org.apache.openjpa.kernel.BrokerImpl.find(BrokerImpl.java:986)
at org.apache.openjpa.kernel.BrokerImpl.find(BrokerImpl.java:880)
at org.apache.openjpa.kernel.DelegatingBroker.find(DelegatingBroker.java:223)
at org.apache.openjpa.persistence.EntityManagerImpl.find(EntityManagerImpl.java:477)
...
Caused by: java.lang.NullPointerException
at org.apache.openjpa.jdbc.kernel.JDBCStoreManager.setInverseRelation(JDBCStoreManager.java:469)
at org.apache.openjpa.jdbc.kernel.JDBCStoreManager.initializeState(JDBCStoreManager.java:429)
at org.apache.openjpa.jdbc.kernel.JDBCStoreManager.initialize(JDBCStoreManager.java:322)
It looks like an error in OpenJPA.Back to mainstream :) - we can narrow the number of queries generated by EclipseLink using @JoinFetch again:
@OneToMany(mappedBy = "employee", fetch = FetchType.EAGER)
@JoinFetch(JoinFetchType.OUTER)
public List getBenefits() {
return benefits;
}
@ManyToOne
@JoinColumn(name = "EMPLOYER_ID")
@JoinFetch(JoinFetchType.OUTER)
public Employer getEmployer() {
return employer;
}
The above will lead to one query (instead of 3):SELECT DISTINCT t1.ID, t1.FIRST_NAME, t1.EMPLOYER_ID, t0.ID, t0.START_DATE, t0.NAME, t0.END_DATE, t0.BENEFIT_TYPE, t0.EMPLOYEE_ID, t2.ID, t2.BUSINESS_NAME
FROM EMPLOYEES t1 LEFT OUTER JOIN BENEFITS t0 ON (t0.EMPLOYEE_ID = t1.ID) LEFT OUTER JOIN EMPLOYERS t2 ON (t2.ID = t1.EMPLOYER_ID)
WHERE (t1.ID = 1)
Finally, let's focus on optional attribute of @ManyToOne annotation. In our example both Employee and Benefit cannot exist without the Employer and Employee respectively, therefore we can change the mapping to:
@ManyToOne(optional = false)
@JoinColumn(name = "EMPLOYER_ID")
public Employer getEmployer() {
return employer;
}
for the Employee, and: @ManyToOne(optional = false)
@JoinColumn(name = "EMPLOYEE_ID")
public Employee getEmployee() {
return employee;
}
for the Benefit.This change will generate queries:
-- Hibernate 3.4.0.GA
select employee0_.id as id1_2_, employee0_.EMPLOYER_ID as EMPLOYER3_1_2_, employee0_.FIRST_NAME as FIRST2_1_2_, benefits1_.EMPLOYEE_ID as EMPLOYEE6_4_, benefits1_.id as id4_, benefits1_.id as id0_0_, benefits1_.EMPLOYEE_ID as EMPLOYEE6_0_0_, benefits1_.END_DATE as END2_0_0_, benefits1_.name as name0_0_, benefits1_.START_DATE as START4_0_0_, benefits1_.BENEFIT_TYPE as BENEFIT5_0_0_, employer2_.id as id2_1_, employer2_.BUSINESS_NAME as BUSINESS2_2_1_
from EMPLOYEES employee0_ left outer join BENEFITS benefits1_ on employee0_.id=benefits1_.EMPLOYEE_ID inner join EMPLOYERS employer2_ on employee0_.EMPLOYER_ID=employer2_.id where employee0_.id=1
-- EclipseLink 2.1.1 (without @JoinFetch)
SELECT ID, FIRST_NAME, EMPLOYER_ID FROM EMPLOYEES WHERE (ID = 1)
SELECT ID, BUSINESS_NAME FROM EMPLOYERS WHERE (ID = 1)
SELECT ID, START_DATE, NAME, END_DATE, BENEFIT_TYPE, EMPLOYEE_ID FROM BENEFITS WHERE (EMPLOYEE_ID = 1)
-- OpenJPA 2.0.1
SELECT t1.id, t1.BUSINESS_NAME, t0.FIRST_NAME, t2.EMPLOYEE_ID, t2.id, t2.END_DATE, t2.name, t2.START_DATE, t2.BENEFIT_TYPE FROM EMPLOYEES t0 INNER JOIN EMPLOYERS t1 ON t0.EMPLOYER_ID = t1.id LEFT OUTER JOIN BENEFITS t2 ON t0.id = t2.EMPLOYEE_ID WHERE t0.id = 1 ORDER BY t2.EMPLOYEE_ID ASC
Don't you think that default behavior of EclipseLink is a little strange? What would we do without the @JoinFetch? When we add it in the following way: @OneToMany(mappedBy = "employee", fetch = FetchType.EAGER)
@JoinFetch(JoinFetchType.OUTER)
public List getBenefits() {
return benefits;
}
@ManyToOne(optional = false)
@JoinColumn(name = "EMPLOYER_ID")
@JoinFetch(JoinFetchType.INNER)
public Employer getEmployer() {
return employer;
}
The world becomes beautiful again:SELECT DISTINCT t1.ID, t1.FIRST_NAME, t1.EMPLOYER_ID, t0.ID, t0.BUSINESS_NAME, t2.ID, t2.START_DATE, t2.NAME, t2.END_DATE, t2.BENEFIT_TYPE, t2.EMPLOYEE_ID
FROM EMPLOYEES t1 LEFT OUTER JOIN BENEFITS t2 ON (t2.EMPLOYEE_ID = t1.ID), EMPLOYERS t0
WHERE ((t1.ID = 1) AND (t0.ID = t1.EMPLOYER_ID))
I know, you are already tired reading the above thoughts ;) - so let's finish for now - we will return to the @OneToMany and @ManyToOne soon with some additional deliberation on cascading and a little more complicated DB examples.The boring part now ;) - read it at your own risk ;) - DB tables and their content (MySQL targeted)
CREATE TABLE BENEFITS (
ID NUMERIC NOT NULL,
EMPLOYEE_ID NUMERIC NOT NULL,
BENEFIT_TYPE VARCHAR(64) NOT NULL,
START_DATE DATE,
END_DATE DATE,
NAME VARCHAR(128),
CONSTRAINT BENEFITS_PK PRIMARY KEY (ID)
);
CREATE TABLE EMPLOYEES (
ID NUMERIC NOT NULL,
EMPLOYER_ID NUMERIC NOT NULL,
FIRST_NAME VARCHAR(64),
CONSTRAINT EMPLOYEES_PK PRIMARY KEY (ID)
);
CREATE TABLE EMPLOYERS (
ID NUMERIC NOT NULL,
BUSINESS_NAME VARCHAR(128),
CONSTRAINT EMPLOYERS_PK PRIMARY KEY (ID)
);
INSERT INTO EMPLOYERS (ID, BUSINESS_NAME) VALUES (1, 'Mighty Ducks');
INSERT INTO EMPLOYEES (ID, EMPLOYER_ID, FIRST_NAME) VALUES (1, 1, 'John');
INSERT INTO EMPLOYEES (ID, EMPLOYER_ID, FIRST_NAME) VALUES (2, 1, 'Mary');
INSERT INTO EMPLOYEES (ID, EMPLOYER_ID, FIRST_NAME) VALUES (3, 1, 'Eugene');
INSERT INTO BENEFITS (ID, EMPLOYEE_ID, BENEFIT_TYPE, START_DATE, END_DATE, NAME)
VALUES(1, 1, 'HEALTH_COVERAGE', '2005-01-01', null, 'Healthy Employees');
INSERT INTO BENEFITS (ID, EMPLOYEE_ID, BENEFIT_TYPE, START_DATE, END_DATE, NAME)
VALUES(2, 1, 'RETIREMENT_PLAN', '2005-01-01', null, 'Gold Autumn');
INSERT INTO BENEFITS (ID, EMPLOYEE_ID, BENEFIT_TYPE, START_DATE, END_DATE, NAME)
VALUES(3, 1, 'GROUP_TERM_LIFE', '2005-01-01', null, 'Always Secured');
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